x^2+7x-184=0

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Solution for x^2+7x-184=0 equation:



x^2+7x-184=0
a = 1; b = 7; c = -184;
Δ = b2-4ac
Δ = 72-4·1·(-184)
Δ = 785
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{785}}{2*1}=\frac{-7-\sqrt{785}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{785}}{2*1}=\frac{-7+\sqrt{785}}{2} $

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